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Subject Topic: PERT QUESTION (Topic Closed Topic Closed) Post ReplyPost New Topic
  
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ngbrian85
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Posted: 10 Feb 2010 at 15:35 | IP Logged  

In a PERT network, the optimistic time for a particular activity is 9 weeks, and the pessimistic time is 21 weeks. Which one of the following is the best estimate of the standard deviation for the activity ?

a) 12

b) 6

c) 2

d) 9

 

The answer eludes me. If you know the answer then post away!

 



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ssham1976
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Posted: 10 Feb 2010 at 15:49 | IP Logged  

wired question

is this AN IT QUESTION

tHE RISK OF THIS SHOWING UP ON THE EXAM IS LOWER than me winning the mega-million jackpot
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ACACPA
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Posted: 12 Feb 2010 at 16:06 | IP Logged  

s = (pessimistic – optimistic)/6

so in this case (21 -9)/6 = 2

Hope it helps

 
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PuyWa
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Posted: 13 Feb 2010 at 00:59 | IP Logged  
Why divided by 6?

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ngbrian85
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Posted: 13 Feb 2010 at 10:38 | IP Logged  
ACACPA wrote:

s = (pessimistic – optimistic)/6

so in this case (21 -9)/6 = 2

Hope it helps

 

 

Thanks, ACACPA.

Aren't you supposed to multiply the optimistic rate by 4 as per the rules ?

 



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AUD - 87 - Jan23/10
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